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Trajectory for Projectile Motion

Following the prescription discussed previously we derive the trajectory for projectile motion by eliminating t from the equations for the horizontal and vertical component of the projectile motion:
eqnarray53
We get the following formula:
 equation59
Here tex2html_wrap_inline240 is the launch angle, ie
equation64
As we had mentioned previously the trajectory for projectile motion is parabolic. There are a few useful expressions which can be derived from this equation. The maximum range on level ground is the distance between y=0 solutions:
equation68
We see that this expression is maximal for tex2html_wrap_inline244 where the range is
equation72
Note that the smaller g the larger range, so we ca throw almost 10 times further on the moon than on earth! Also note that the range decreases for steeper as well as for shallower angleswhich means that for any range less than max-range there are two elevations which will mach. Highest elevation always keeps the projectile in air longer so if we want to get there fast we use the lower elevation.

Another interesting characteristic of projectile motion is the max height. To determine it we need only consider the motion in the y-direction. The following equation holds for this motion with constant acceleration:
equation77
At maximum height we have tex2html_wrap_inline250. We insert this value in the equation and solve for h to get
equation81
Remember that these formulae only hold for projectile motion on flat ground. For more complicated cases you will have to work the formulae for tex2html_wrap_inline254 and the trajectory yourself so make sure you understand what went on in these derivations.





Collin Broholm
Tue Sep 16 16:33:10 EDT 1997